LeetCode 69 (lol) - Sqrt(x) Problem

Problem Statement

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.


class Solution: def mySqrt(self, x: int) -> int: low=0 high=x if x<2: return x while lowx: high=mid else: low=mid+1 return low-1